(w^2-10w+21)/(27-3w^2)

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Solution for (w^2-10w+21)/(27-3w^2) equation:


D( w )

27-(3*w^2) = 0

27-(3*w^2) = 0

27-(3*w^2) = 0

27-3*w^2 = 0

-3*w^2 = -27 // : -3

w^2 = 9

w^2 = 9 // ^ 1/2

abs(w) = 3

w = 3 or w = -3

w in (-oo:-3) U (-3:3) U (3:+oo)

(w^2-(10*w)+21)/(27-(3*w^2)) = 0

(w^2-10*w+21)/(27-3*w^2) = 0

w^2-10*w+21 = 0

w^2-10*w+21 = 0

DELTA = (-10)^2-(1*4*21)

DELTA = 16

DELTA > 0

w = (16^(1/2)+10)/(1*2) or w = (10-16^(1/2))/(1*2)

w = 7 or w = 3

(w-3)*(w-7) = 0

((w-3)*(w-7))/(27-3*w^2) = 0

( w-3 )

w-3 = 0 // + 3

w = 3

( w-7 )

w-7 = 0 // + 7

w = 7

w in { 3}

w = 7

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